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Lecture Notes | Approved: 7 years ago | 913.5 kB | Comments: 0
Category: Electromagnetic Theory | Downloaded: 0
...symmetry should simplify the calculations. Field Due...
...Use spheres as the gaussian surfaces When...
...When r a, the charge inside the...
...the charge inside the surface is Q...
...When r a, the charge inside the...
...the charge inside the surface is 0...
...of Charge, cont. The end view confirms...
...end view confirms the field is perpendicular...
...is perpendicular to the curved surface The...
...perpendicular to the curved surface The field...
...the curved surface The field through the...
...The field through the ends of the...
...the ends of the cylinder is 0...
...is 0 since the field is parallel...
...be perpendicular to the plane and must...
...and must have the same magnitude at...
...points equidistant from the plane Choose a...
...is perpendicular to the plane for the...
...the plane for the gaussian surface Field...
...is parallel to the curved surface and...
...parallel to the curved surface and there...
...no contribution to the surface area from...
...area from this curved part of the...
...curved part of the cylinder The flux...
...of the cylinder The flux through each...
...each end of the cylinder is EA...
...EA and so the total flux is...
...1040U (Physics for the biosciences) Introduction to...
...can consider of the rod and multiply...
...we consider only the x component. dy...
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